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Analog Electronics – Problems Page 29

h-Parameter Analysis & Gain Calculations

This section focuses on transistor amplifier analysis using hybrid h-parameters such as hie, hfe, hre and hoe. These parameters are widely used in small-signal analysis of BJT amplifiers.

                                       

Picture used in analog electronics


Basic h-Parameter Equations

V1 = h11 I1 + h12 V2

I2 = h21 I1 + h22 V2

For common emitter configuration:

h11 = hie (input resistance)

h21 = hfe (current gain)

h12 = hre (reverse voltage gain)

h22 = hoe (output admittance)


Voltage Gain Formula

The approximate voltage gain of a CE amplifier using h-parameters is:

Av ≈ − (hfe RL) / hie


Problem 1

A transistor amplifier has hfe = 100, hie = 1 kΩ and load resistance RL = 4 kΩ. Calculate voltage gain.

Solution

Av = − (hfe × RL) / hie

Av = − (100 × 4000) / 1000

Av = −400


Problem 2

If hie = 2 kΩ and input voltage Vin = 10 mV, find base current.

Solution

Ib = Vin / hie

Ib = 10mV / 2kΩ

Ib = 5 μA


Problem 3

If hfe = 120 and base current Ib = 20 μA, find collector current.

Solution

Ic = hfe × Ib

Ic = 120 × 20 μA

Ic = 2.4 mA


Problem 4

A CE amplifier has hie = 1.5 kΩ, hfe = 80 and RL = 3 kΩ. Calculate voltage gain.

Solution

Av = − (hfe × RL) / hie

Av = − (80 × 3000) / 1500

Av = −160


Problem 5

If reverse voltage gain hre is very small, what is the effect?

Solution

  • Reverse feedback becomes negligible
  • Amplifier analysis becomes simpler
  • Voltage gain mainly depends on hfe and hie

 

Analog Electronics – Problems Page 28

Rapid Fire MCQs for GATE Revision

This section contains quick multiple choice questions from analog electronics useful for rapid revision before examinations.


MCQ 1

The thermal voltage at room temperature is approximately:

A) 10 mV B) 25 mV C) 50 mV D) 100 mV

Answer: B (25 mV)


MCQ 2

Which diode is used for voltage regulation?

A) Tunnel diode B) Zener diode C) LED D) Photodiode

Answer: B (Zener diode)


MCQ 3

In a BJT transistor:

A) IC = β IB B) IC = α IB C) IC = IE D) IC = IB

Answer: A


MCQ 4

The input impedance of an ideal op-amp is:

A) Zero B) Infinite C) Very small D) 1 kΩ

Answer: B (Infinite)


MCQ 5

The output impedance of an ideal op-amp is:

A) Infinite B) Zero C) 1 kΩ D) Very large

Answer: B (Zero)


MCQ 6

The Barkhausen criterion for oscillation is:

A) Aβ = 0 B) Aβ = 1 C) Aβ = 10 D) Aβ = 100

Answer: B


MCQ 7

The oscillator commonly used for audio frequency generation is:

A) Hartley oscillator B) Colpitts oscillator C) RC phase shift oscillator D) Crystal oscillator

Answer: C


MCQ 8

The cutoff frequency of an RC filter is:

A) 1/RC B) 1/(2πRC) C) RC D) 2πRC

Answer: B


MCQ 9

Which oscillator uses capacitive divider?

A) Hartley oscillator B) Colpitts oscillator C) Wien bridge oscillator D) RC oscillator

Answer: B


MCQ 10

The ripple factor of full wave rectifier is:

A) 0.121 B) 0.482 C) 1.21 D) 2

Answer: B

 

Analog Electronics – Problems Page 27

Ultra Hard Multi-Concept Problems (GATE Level)

This section contains multi-concept problems combining diode circuits, transistor amplifiers, op-amp circuits and oscillators.


Problem 1

A silicon diode conducts 2 mA current when forward voltage is 0.7 V. Find the dynamic resistance at this operating point.

Solution

rd = VT / I

VT = 25 mV

rd = 0.025 / 0.002

rd = 12.5 Ω


Problem 2

A BJT transistor has β = 100 and collector current IC = 2 mA. Find the transconductance gm.

Solution

gm = IC / VT

gm = 0.002 / 0.025

gm = 0.08 S


Problem 3

An op-amp inverting amplifier has Rin = 2 kΩ and Rf = 20 kΩ. If Vin = 0.2 V, calculate output voltage.

Solution

Av = −Rf / Rin

Av = −20k / 2k = −10

Vo = Av × Vin

Vo = −10 × 0.2 = −2 V


Problem 4

A Hartley oscillator uses L1 = 3 mH, L2 = 7 mH and C = 150 pF. Find oscillation frequency.

Solution

Total inductance

L = L1 + L2 = 10 mH

f = 1 / (2π√LC)

f ≈ 130 kHz


Problem 5

An op-amp differential amplifier has Ad = 3000 and Ac = 0.3. Find CMRR in dB.

Solution

CMRR = Ad / Ac

CMRR = 3000 / 0.3 = 10000

CMRR(dB) = 20 log (10000)

CMRR = 80 dB


Problem 6

An RC oscillator uses R = 8 kΩ and C = 0.02 μF. Find oscillation frequency.

Solution

f = 1 / (2πRC)

f ≈ 995 Hz

 

Analog Electronics – Problems Page 26

GATE Previous Year Type Questions

This section contains important conceptual and numerical questions inspired by previous GATE examinations.


Problem 1

A silicon diode is forward biased with voltage 0.7 V. The thermal voltage is 25 mV. Calculate exponential factor V/VT.

Solution

V / VT = 0.7 / 0.025

V/VT = 28


Problem 2

A transistor has β = 150 and emitter current IE = 3 mA. Find collector current IC.

Solution

Relation:

IC ≈ α IE

Where

α = β / (1 + β)

α = 150 / 151 ≈ 0.993

IC ≈ 2.98 mA


Problem 3

An op-amp has open loop gain 10⁵. If feedback factor β = 0.01, find closed loop gain.

Solution

Acl = A / (1 + Aβ)

Acl = 10⁵ / (1 + 10⁵ × 0.01)

Acl ≈ 100


Problem 4

A low pass filter has R = 1 kΩ and C = 0.1 μF. Find cutoff frequency.

Solution

fc = 1 / (2πRC)

fc ≈ 1591 Hz


Problem 5

In an RC phase shift oscillator, how many RC sections are used?

3 RC sections


Problem 6

A Wien bridge oscillator has R = 20 kΩ and C = 0.005 μF. Calculate oscillation frequency.

Solution

f = 1 / (2πRC)

f ≈ 1592 Hz


Problem 7

What is the ideal value of CMRR for an op-amp?

Infinite


Problem 8

Which oscillator is commonly used in RF circuits?

Hartley or Colpitts oscillator

 

Analog Electronics – Problems Page 25

Very Hard Numerical Problems (GATE Level)

This section contains advanced numerical problems combining diode circuits, BJT amplifiers, operational amplifiers and oscillators.


Problem 1

A silicon diode has reverse saturation current Is = 10⁻¹² A. Calculate diode current when forward voltage is 0.7 V at room temperature.

Solution

Diode equation: I = Is (e^(V/VT) − 1)

At room temperature:

VT ≈ 25 mV

Substitute values:

I = 10⁻¹² (e^(0.7/0.025) − 1)

I ≈ 1.2 mA


Problem 2

A BJT amplifier has Rc = 4 kΩ and re = 25 Ω. Find the voltage gain of the CE amplifier.

Solution

Av = −Rc / re

Av = −4000 / 25 Av = −160


Problem 3

An inverting op-amp has Rin = 5 kΩ and Rf = 50 kΩ. If input voltage is 0.1 V, calculate output voltage.

Solution

Av = −Rf / Rin

Av = −50k / 5k = −10

Vo = Av × Vin Vo = −10 × 0.1 = −1 V


Problem 4

An LC oscillator uses L = 2 mH and C = 200 pF. Find oscillation frequency.

Solution

f = 1 / (2π√LC)

f ≈ 251 kHz


Problem 5

An op-amp differential amplifier has Ad = 2000 and Ac = 0.5. Calculate CMRR in dB.

Solution

CMRR = Ad / Ac

CMRR = 2000 / 0.5 = 4000

CMRR(dB) = 20 log(4000)

CMRR ≈ 72 dB


Problem 6

A Wien bridge oscillator uses R = 10 kΩ and C = 0.01 μF. Find oscillation frequency.

Solution

f = 1 / (2πRC)

f ≈ 1591 Hz

 

Analog Electronics – Problems Page 24

Mixed Concept & Numerical Problems

This section includes mixed questions from diode circuits, BJT amplifiers, operational amplifiers and oscillators for GATE preparation.


Problem 1

Find the thermal voltage at room temperature (300 K).

Solution

VT = kT / q

VT ≈ 25 mV


Problem 2

A BJT has β = 120 and base current 20 μA. Find collector current.

Solution

Ic = β × Ib

Ic = 120 × 20 μA Ic = 2.4 mA


Problem 3

Calculate the voltage gain of an inverting op-amp with Rf = 100 kΩ and Rin = 10 kΩ.

Solution

Av = −Rf / Rin

Av = −100k / 10k Av = −10


Problem 4

An LC oscillator has L = 5 mH and C = 100 pF. Find oscillation frequency.

Solution

f = 1 / (2π√LC)

f ≈ 225 kHz


Problem 5

What is the ripple factor of a full wave rectifier?

Ripple Factor = 0.482


Problem 6

What is the ideal input impedance of an operational amplifier?

Infinite


Problem 7

What is the ideal output impedance of an op-amp?

Zero


Problem 8

For oscillations to occur, what should be the loop gain?

Aβ = 1

This is the Barkhausen criterion.

 

Analog Electronics – Problems Page 23

Oscillator Advanced Numerical Problems

This section contains advanced numerical problems on oscillator circuits useful for GATE and PSU examinations.

                                     

Picture used in analog electronics


Problem 1

An RC phase shift oscillator uses R = 5 kΩ and C = 0.02 μF. Find the oscillation frequency.

Solution

Formula:

f = 1 / (2πRC√6)

Substitute values:

f = 1 / (2π × 5000 × 0.02×10⁻⁶ × √6)

Result:

f ≈ 650 Hz


Problem 2

A Hartley oscillator has inductors L1 = 4 mH and L2 = 6 mH with capacitor C = 200 pF. Calculate the oscillation frequency.

Solution

Total inductance:

L = L1 + L2 = 10 mH

Formula:

f = 1 / (2π√LC)

Substitute:

f = 1 / (2π √(10×10⁻³ × 200×10⁻¹²))

Result:

f ≈ 112 kHz


Problem 3

A Colpitts oscillator has capacitors C1 = 100 pF, C2 = 400 pF and inductor L = 2 mH. Find the oscillation frequency.

Solution

Equivalent capacitance:

Ceq = (C1C2)/(C1 + C2)

Substitute:

Ceq = (100×400)/(500)

Ceq = 80 pF

Frequency:

f = 1/(2π√LC)

Result:

f ≈ 125 kHz


Problem 4

A crystal oscillator has inductance L = 0.5 H and capacitance C = 0.02 pF. Calculate the series resonant frequency.

Solution

Formula:

f = 1/(2π√LC)

Substitute values:

f = 1/(2π √(0.5 × 0.02×10⁻¹²))

Result:

f ≈ 1.59 MHz


Problem 5

An oscillator has amplifier gain A = 10 and feedback factor β = 0.1. Check whether oscillations will occur.

Solution

Loop gain:

Aβ = 10 × 0.1

Aβ = 1

Since loop gain equals 1,

Oscillations will occur.

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