Showing posts with label Electrical Engineering. Show all posts
Showing posts with label Electrical Engineering. Show all posts

Monday, 23 February 2026

 

πŸ“˜ Power Systems – Mega Revision Formula Sheet (Page 20)

Final rapid revision formulas for GATE + PSU.


πŸ”Ή Per Unit System

Base Current: I_base = S_base / (√3 V_base) Base Impedance: Z_base = V_base² / S_base Per Unit Value: PU = Actual / Base

πŸ”Ή Fault Analysis

3-Phase Fault Current: I_f = V / Z_total SLG Fault Current: I_f = 3V / (Z1 + Z2 + Z0) Fault MVA: MVA_fault = √3 V I If impedance reduces by x%, fault current increases by 1/(1-x)

πŸ”Ή Transmission Lines

Surge Impedance: Z_s = √(L/C) SIL = V² / Z_s Short line → Ignore capacitance Medium line → Nominal Ο€ Long line → Hyperbolic equations

πŸ”Ή Stability

Power Equation (SMIB): P = (EV/X) sinΞ΄ Maximum Power: P_max = EV / X Swing Equation: M d²Ξ΄/dt² = P_m - P_e Maximum power at Ξ΄ = 90°

πŸ”Ή Economic Dispatch

Incremental Cost: dC/dP = Ξ» With Losses: (dC/dP) × Penalty Factor = Ξ» Penalty Factor: 1 / (1 - ∂P_L/∂P_i)

πŸ”Ή Load Flow

Gauss-Seidel → Linear convergence Newton-Raphson → Quadratic convergence Slack Bus → V & angle fixed PV Bus → P & V fixed PQ Bus → P & Q specified

πŸ”Ή HVDC

Power = V × I Advantages:
  • No reactive power flow
  • No stability limit
  • Lower losses for long distance

πŸ”Ή Protection

Distance Relay → Measures impedance Zone 1 → 80% line Differential Relay → Based on KCL PSM = Fault Current / Relay Setting

πŸ”Ή Load Factors

Load Factor = Average Load / Peak Load Diversity Factor = Sum of Individual Max / System Max

Page 20 – Mega Revision Formula Sheet Completed

πŸ”₯ Power Systems Complete Master Module (20 Pages) Achieved πŸ”₯

 

πŸ“˜ Distance Protection – Zone Setting & Numerical Problems

Distance relay measures impedance (Z = V/I) and operates when measured impedance is less than preset zone impedance.


πŸ”Ή 1️⃣ Basic Principle

Z = V / I

  • Short circuit → Current increases
  • Measured impedance decreases
  • If Z_measured < Z_set → Relay trips

πŸ”Ή 2️⃣ Zone Settings

  • Zone 1 → 80% of protected line (Instantaneous)
  • Zone 2 → 100% line + 50% next line (Time delay)
  • Zone 3 → Backup (Further reach)

πŸ”Ή Problem 1: Zone 1 Setting

Line impedance = 0.5 + j4 Ξ© Length = 100 km Find Zone 1 setting.

Solution

Total impedance magnitude = √(0.5² + 4²) = √(0.25 + 16) = √16.25 = 4.03 Ξ©

Zone 1 = 80% × 4.03 = 3.22 Ξ©


πŸ”Ή Problem 2: Fault at 60 km

Fault occurs at 60 km on same line. Will Zone 1 operate?

Step 1: Fault Impedance

Impedance per km = 4.03 / 100 = 0.0403 Ξ©/km Fault impedance = 60 × 0.0403 = 2.418 Ξ©

Since 2.418 < 3.22 → Zone 1 trips instantly.


πŸ”Ή Problem 3: Zone 2 Setting

Adjacent line impedance = 3 Ξ© Calculate Zone 2 setting.

Solution

Zone 2 = Line impedance + 50% next line = 4.03 + (0.5 × 3) = 4.03 + 1.5 = 5.53 Ξ©


πŸ”Ή Problem 4: Measured Voltage & Current

Measured V = 11 kV Measured I = 1000 A Find measured impedance.

Solution

Z = V / I = 11000 / 1000 = 11 Ξ©

If Zone setting = 5 Ξ©:

Since 11 > 5 → Relay does NOT operate.


πŸ“Š Types of Distance Relays

  • Impedance Relay
  • Reactance Relay
  • Mho Relay (most common)

🎯 GATE & Interview Points

  • Distance relay independent of fault current magnitude
  • Zone 1 is instantaneous
  • Zone 2 and 3 are time delayed
  • Mho relay has circular characteristic

Distance Protection = Impedance Based Intelligent Protection

Sunday, 22 February 2026

 

πŸ“˜ Derivations of Unsymmetrical Fault Currents

                                         
Picture used in power systems

We derive LG, LL and LLG fault currents using symmetrical components. Assume prefault voltage V = 1 pu.


πŸ”Ή 1️⃣ Single Line-to-Ground (LG) Fault Derivation

Assume phase 'a' is grounded: Va = 0 Ib = Ic = 0 Using symmetrical components: Ia = I1 + I2 + I0 For LG fault: I1 = I2 = I0 Why? Because boundary condition forces equal sequence currents. Now: Ia = 3I1 Sequence network connection: Z1, Z2, Z0 connected in series. Voltage equation: V = I1 Z1 + I2 Z2 + I0 Z0 Since I1 = I2 = I0: V = I1 (Z1 + Z2 + Z0) Therefore: I1 = V / (Z1 + Z2 + Z0) Total fault current: Ia = 3I1

I_fault = 3V / (Z1 + Z2 + Z0)


πŸ”Ή 2️⃣ Line-to-Line (LL) Fault Derivation

Assume phase b and c shorted: Ib = -Ic Ia = 0 Symmetrical component condition: I0 = 0 I1 = -I2 Zero sequence current absent. Sequence network: Z1 and Z2 in series. Voltage equation: V = I1 Z1 + I2 Z2 Since I2 = -I1: V = I1 (Z1 + Z2) Thus: I1 = V / (Z1 + Z2) Phase fault current: I_fault = √3 I1

I_fault = √3 V / (Z1 + Z2)


πŸ”Ή 3️⃣ Double Line-to-Ground (LLG) Fault Derivation

Assume b and c shorted to ground. Boundary conditions: Va ≠ 0 Vb = 0 Vc = 0 Sequence currents satisfy: I1 + I2 + I0 = 0 Sequence network: Z2 and Z0 in parallel Then in series with Z1. Equivalent impedance: Z_eq = Z1 + (Z2 Z0)/(Z2 + Z0) Thus: I1 = V / Z_eq Total fault current: Ia = 3I1

I_fault = 3V / (Z1 + (Z2 Z0)/(Z2 + Z0))


πŸ“Š Key Comparison from Derivation

Fault Type Sequence Network Connection Formula
LG Z1 + Z2 + Z0 (Series) 3V/(Z1+Z2+Z0)
LL Z1 + Z2 √3V/(Z1+Z2)
LLG Z1 + (Z2 || Z0) 3V/(Z1+(Z2Z0)/(Z2+Z0))

🎯 Important Conceptual Insights

  • LG fault → all three sequence currents equal
  • LL fault → zero sequence absent
  • LLG fault → mixed parallel connection
  • Grounding strongly affects Z0

Fault Derivation = Boundary Conditions + Sequence Network Logic

 

πŸ“š GATE Electrical – Signals & Systems Complete Library

This page contains complete structured coverage of Signals & Systems for GATE Electrical Engineering including theory, worked examples and advanced concepts.


 MODULE 1 – SIGNAL BASICS


MODULE 2 – SYSTEM PROPERTIES


 CONVOLUTION


 FOURIER SERIES


 FOURIER TRANSFORM


 Z-TRANSFORM


 SAMPLING THEOREM


Signals & Systems – Complete Coverage for GATE Electrical Engineering

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