📘 Single Phase Induction Motor – Numerical Problems
Numerical problems are mainly based on double revolving field theory. Forward and backward rotating fields must be considered.
🔹 Problem 1 – Slip Calculation
Given: Frequency = 50 Hz Number of poles = 4 Rotor speed = 1440 rpm Find slip. Step 1: Synchronous speed Ns = 120f / P = 120 × 50 / 4 = 1500 rpm Step 2: Slip s = (Ns − Nr) / Ns = (1500 − 1440)/1500 = 60/1500Slip = 0.04 or 4%
🔹 Problem 2 – Forward and Backward Slip
Given slip s = 0.04 Forward field slip = s = 0.04 Backward field slip: s_b = 2 − s = 2 − 0.04Backward slip = 1.96
Important concept: Backward slip always close to 2.🔹 Problem 3 – Air Gap Power
Given: Rotor input power = 1000 W Slip = 0.05 Mechanical power developed: P_mech = Rotor input × (1 − s) = 1000 × (1 − 0.05) = 1000 × 0.95P_mech = 950 W
Rotor copper loss: = s × Rotor input = 0.05 × 1000Rotor copper loss = 50 W
🔹 Problem 4 – Starting Torque Ratio
If starting torque = 1.5 times full load torque, And full load torque = 20 NmStarting torque = 30 Nm
Conceptual understanding question.🔹 Problem 5 – Output Power
Given: Mechanical power developed = 950 W Mechanical losses = 50 W Output power: = 950 − 50Output power = 900 W
🔹 Important Concepts to Remember
- Single phase IM behaves like two induction motors
- Forward slip = s
- Backward slip = 2 − s
- Net torque = Forward torque − Backward torque
- At starting, net torque = 0
🎯 GATE Important Points
- Backward slip formula very important
- Rotor copper loss = s × Rotor input
- Mechanical power = (1 − s) × Rotor input
- Forward & backward torque concept common question
Single Phase IM = Double Revolving Field Theory
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