📘 GATE Electrical – Network Theory Advanced Practice Set (KCL & KVL) – Part B
📌 Problem 5 – Supernode Analysis
✔ Solution:
Since a voltage source connects V1 and V2 → Use Supernode.
Equation 1 (Supernode KCL):
V1/5 + V2/10 = 0
Equation 2 (Voltage constraint):
V1 − V2 = 10
Solve equations:
Multiply first equation by 10:
2V1 + V2 = 0 ...(1)
V1 = V2 + 10 ...(2)
Substitute (2) into (1):
2(V2 + 10) + V2 = 0 2V2 + 20 + V2 = 0 3V2 = −20 V2 = −6.67V
V1 = 3.33V
📌 Problem 6 – Dependent Source (GATE Level)
✔ Solution Outline:
Let current through 10Ω = I
Then Vx = 10I
Dependent source = 0.1 × 10I = I
Apply KCL:
20 − 10I − V = 0 (after simplification)
Solving gives:
📌 Problem 7 – Three Mesh Analysis
✔ Mesh Equations:
(4 + 2 + 2)I1 − 2I2 − 2I3 = 15 −2I1 + (4 + 2 + 2)I2 − 2I3 = 0 −2I1 − 2I2 + (4 + 2 + 2)I3 = 0
After solving simultaneous equations:
📌 Problem 8 – Maximum Power Condition (Using KCL/KVL)
✔ Solution:
Maximum power occurs when:
RL = Rth
🎯 Advanced Exam Insights
- ✔ Voltage source between nodes → Think Supernode
- ✔ Dependent source → Express variable clearly
- ✔ Mesh method preferred when loops < nodes
- ✔ Speed + clarity = Rank improvement
Advanced Problems Complete. Next: Superposition Theorem – Full GATE Level Series.
No comments:
Post a Comment