Friday, 27 February 2026

 

Page 63 – Ultra Hard Mixed DC-DC Numerical Test

Subject: Power Electronics
Level: GATE / PSU Advanced


🔹 Problem 1 – Identify Mode + Output Voltage

Buck-Boost converter: Vin = 15 V D = 0.5 L = 50 μH fs = 40 kHz R = 5 Ω Determine:
1) CCM or DCM
2) Output voltage

Step 1 – Find Lcritical

Lcritical = R(1−D)² / (2fs) = 5(0.5)² / (2×40000) = 5(0.25) / 80000 = 1.25 / 80000 = 15.6 μH

Given L = 50 μH > Lcritical → CCM

Step 2 – Output Voltage

Vo/Vin = −D/(1−D) = −0.5/0.5 = −1 Vo = −15 V

Final Answer: CCM, Vo = −15 V

🔹 Problem 2 – Boost Converter Ripple

Vin = 20 V D = 0.6 L = 200 μH fs = 25 kHz Find inductor ripple current.

ΔIL = Vin D / (L fs) = 20×0.6 / (200×10⁻⁶ × 25000) = 12 / 5 = 2.4 A

Answer: 2.4 A

🔹 Problem 3 – SEPIC Duty Cycle

Vin varies 10–20 V Vo = 15 V Find duty cycle range.

Vo/Vin = D/(1−D) Case 1: Vin = 10 15/10 = 1.5 1.5 = D/(1−D) D = 0.6 Case 2: Vin = 20 15/20 = 0.75 0.75 = D/(1−D) D = 0.43

Duty cycle range: 0.43 – 0.6

🔹 Problem 4 – Ćuk Converter Power

Vin = 12 V D = 0.5 R = 8 Ω Find output power.

Vo/Vin = −D/(1−D) = −0.5/0.5 = −1 Vo = −12 V Io = 12/8 = 1.5 A P = Vo × Io = 12 × 1.5 = 18 W

Answer: 18 W

🔹 Problem 5 – DCM Output

Vin = 24 V D = 0.4 R = 20 Ω L = 100 μH fs = 50 kHz Find Vo (DCM).

Vo/Vin = − (D² R) / (2Lfs) = − (0.16 × 20) / (2×100×10⁻⁶ × 50000) = − (3.2) / (10) = −0.32 Vo = −0.32 × 24 = −7.68 V

Final Answer: −7.68 V

 Master Concept Summary

✔ CCM → Gain depends only on D ✔ DCM → Gain depends on R, L, fs ✔ Always check Lcritical ✔ SEPIC = Non-inverting ✔ Ćuk = Low ripple ✔ Buck-Boost = Inverting


Ultra Hard DC-DC Series – Shaktimatha Learning

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