📘 Corona – Numerical Problems (GATE Level)
These problems focus on critical disruptive voltage and corona loss calculations.
🔹 Problem 1 – Critical Disruptive Voltage
Given: r = 1.2 cm D = 120 cm m0 = 0.9 δ = 1 Formula: Vd = 21.1 m0 δ r ln(D/r) Step 1: ln(D/r) = ln(120/1.2) = ln(100) ≈ 4.6 Step 2: Vd = 21.1 × 0.9 × 1 × 1.2 × 4.6 = 21.1 × 4.968 ≈ 104.8 kV per phaseCritical disruptive voltage ≈ 105 kV
🔹 Problem 2 – Effect of Altitude
Given: δ = 0.8 (high altitude) All other values same as Problem 1. Since: Vd ∝ δ New Vd: = 0.8 × 105Vd ≈ 84 kV
Conclusion: Higher altitude → lower air density → lower corona voltage.🔹 Problem 3 – Effect of Conductor Radius
Original radius = 1 cm New radius = 2 cm Since: Vd ∝ r ln(D/r) Increasing radius increases Vd. Therefore: Larger conductor → less corona. Very common conceptual GATE question.🔹 Problem 4 – Corona Loss Concept
Given: Operating voltage = 120 kV Critical voltage = 100 kV Corona occurs only when: V > Vd Since 120 > 100,Corona will occur.
If voltage < Vd → No corona.🔹 Problem 5 – Comparative Question
Two lines: Line A: r = 1 cm Line B: r = 2 cm Which has more corona loss? Since larger radius increases Vd,Line A will have more corona loss.
🔹 Problem 6 – Multiple Choice Type
Corona is reduced by: A) Increasing conductor spacing B) Increasing conductor radius C) Increasing air pressure D) All of the aboveAnswer: D
🎯 GATE Important Observations
- Corona increases with voltage
- Corona decreases with conductor radius
- High altitude increases corona
- Bad weather increases corona
Corona = High Voltage Surface Ionization Phenomenon
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