Monday, 23 February 2026

 

📘 Protection Coordination – Time & Current Grading (Numerical Problems)

Protection coordination ensures that only the faulty section is isolated. Primary relay must operate first, backup relay operates after delay.


🔹 Problem 1: Time Grading

Two overcurrent relays R1 (near load) and R2 (upstream). Relay R1 operates in 0.4 sec. Coordination Time Interval (CTI) = 0.3 sec. Find operating time of R2.

Solution

Operating time of R2 = R1 time + CTI = 0.4 + 0.3 = 0.7 sec

Upstream relay must operate at 0.7 sec.


🔹 Problem 2: Plug Setting Calculation

CT ratio = 500/1 Full load current = 250 A Relay plug setting = 125% Find pickup current.

Step 1: Secondary Current at Full Load

Secondary current = 250 / 500 = 0.5 A

Step 2: Pickup Current

Pickup = 1.25 × 0.5 = 0.625 A


🔹 Problem 3: Plug Setting Multiplier (PSM)

Fault current = 2000 A CT ratio = 500/1 Pickup current (secondary) = 1 A Find PSM.

Step 1: Convert Fault to Secondary

Secondary fault current = 2000 / 500 = 4 A

Step 2: Calculate PSM

PSM = Fault current / Pickup current = 4 / 1 = 4


🔹 Problem 4: Inverse Time Relay Operation

Relay characteristic: T = 0.14 / (PSM^0.02 − 1) Given PSM = 5 Find operating time.

Solution

PSM^0.02 ≈ 1.032 T = 0.14 / (1.032 − 1) = 0.14 / 0.032 = 4.375 sec


🔹 Problem 5: Current Grading

Relay R1 pickup = 1 A Relay R2 pickup = 1.5 A Fault current = 4 A Check which operates first.

Solution

PSM1 = 4 / 1 = 4 PSM2 = 4 / 1.5 = 2.67

Higher PSM → Faster operation.

Relay R1 operates first (Primary protection).


🎯 Key Coordination Concepts

  • CTI typically 0.2–0.5 sec
  • Primary protection fastest
  • Backup protection time delayed
  • Plug setting multiplier decides relay speed

Protection Coordination = Selectivity + Reliability + Speed

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